MathematicsGeneralQuality 88 · Exceptional

Deriving the Quadratic Formula

PR
Valentina KellyTeacher Tier
@author · 2026-08-21 · v1
7 min read
Start from
ax2+bx+c=0ax^2+bx+c=0
. Divide by
aa
(assuming
a≠0a\neq 0
):
x2+bax+ca=0x^2+\frac{b}{a}x+\frac{c}{a}=0
. Complete the square by adding
(b2a)2\left(\frac{b}{2a}\right)^2
to both sides, factor the left, then take the square root. The familiar
x=−b±b2−4ac2ax=\frac{-b\pm\sqrt{b^2-4ac}}{2a}
falls out. The expression under the root,
b2−4acb^2-4ac
, is the discriminant: its sign tells you whether there are two, one, or zero real solutions.
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